A simple pendulum has time period ‘$T_1$’. The point of suspension is now moved upwards according to the relation $y=k{t}^2,\left(k=1m/{\sec }^2\right)$ where y is the vertical displacement.  The time period now becomes ‘$T_2$’  then find the ratio of $\frac{T_1^2}{T_2^2}\left(g=10m/{\sec }^2\right)$