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A simple pendulum is hanging from a peg inserted in a vertical wall. Its bob is stretched to horizontal position from wall and is left free to move, the bob hits the wall. If coefficient of restitution is 2/√5. After how many collisions the amplitude of vibration will become less than 600.

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answer is B.

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Detailed Solution

$\begin{array}{l} h_{n} = {he}^{2 n} = h [1 - \cos 60] \\ e^{2 n} = \frac{1}{2} \Rightarrow {(\frac{2}{\sqrt{5}})}^{2 n} = \frac{1}{2} \end{array}$

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