A simple pendulum is of length 50cm. Find its time period and frequency of oscillation. (g = 9.8 m/s2).

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A simple pendulum is of length 50cm. Find its time period and frequency of oscillation. (g = 9.8 m/s²).

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5.619 sec, 0.6045Hz

3.219 sec, 0.5045Hz

1.419 sec, 0.7045Hz

2.419 sec, 0.8045Hz

answer is D.

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Detailed Solution

$\begin{array}{l} T = 2 π \sqrt{\frac{ℓ}{g}} = 2 π \sqrt{\frac{50 / 100}{9 .8}} = 1 .419 \sec \\ n = \frac{1}{T} = 0 .7045 \end{array}$

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