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Q.

A simple pendulum is of length 50cm. Find its time period and frequency of oscillation. (g = 9.8 m/s2).

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a

2.419 sec, 0.8045Hz

b

3.219 sec, 0.5045Hz

c

5.619 sec, 0.6045Hz

d

1.419 sec, 0.7045Hz

answer is D.

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Detailed Solution

T=2πg=2π50/1009.8=1.419secn=1T=0.7045

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