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A simple pendulum is oscillating with an angular amplitude 60^o. If mass of bob is 50 gram, then the tension in the string at mean position is (g = 10ms^–2)

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1 N

1.5 N

0.5 N

2 N

answer is B.

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Detailed Solution

$T = mg + \frac{{mv}^{2}}{r} = mg + \frac{m}{l} [2 gl (1 - \cos θ)]$ if $θ = 60^{0}$

T=2mg

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