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A simple pendulum is released from A as shown in figure. If 'm' and 'l' represent the mass of bob and the length of pendulum respectively, the gain in kinetic energy at B is :

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$\frac{mgl}{2}$

$\frac{mgl}{\sqrt{2}}$

$\frac{\sqrt{3}}{2} mgl$

$\frac{2}{\sqrt{3}} mgl$

answer is A.

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Detailed Solution

Gain in KE = Loss in PE = mgl sin 30° $= \frac{mgl}{2}$

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