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Q.

A simple pendulum is swinging in a vertical plane. Its highest point above ground is 40cm.If the maximum velocity of the pendulum is 1.4 $m s^{- 1}$ , its lowest position above ground is

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a

20 cm

b

25 cm

c

40 cm

d

30 cm

answer is C.

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Detailed Solution

$\frac{1}{2} m v^{2} = m g (h_{1} - h_{2})$

$\frac{1}{2} \times 1.4 \times 1.4 = 9.8 (40 - h_{2}) \times 10^{- 2}$

$\Rightarrow h_{2} = 30 c m$

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A simple pendulum is swinging in a vertical plane. Its highest point above ground is 40cm.If the maximum velocity of the pendulum is 1.4ms−1 , its lowest position above ground is