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Q.

A simple pendulum of length 1 m is oscillated at a place where g=9.8m/s2 . Find the maximum velocity of the bob of the simple pendulum if the amplitude of oscillation is 3cm.

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a

7.261cms-1

b

9.42 cms-1

c

5.291cms-1

d

6.181cms-1

answer is D.

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Detailed Solution

detailed_solution_thumbnail

 Vmax=Aω

ω for simple pendulum=gl=9.81≈π=3.14

Vmax=Aω=3x3.14=9.42 cm/sec

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