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Q.

A simple pendulum of length l and bob of mass m is displaced from its equilibrium position O to a position P so that height of P above O is h. It is then released. What is the tension in the string when the bob passes through the equilibrium position O? Neglect friction. V is the velocity of the bob at O

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a

1 and 4 both are correct.

b

mg(1+hl)

c

m(g+v2l)

d

mg(1+2hl)

answer is B.

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Detailed Solution

From equation of motion v2=2gh

For vertical circular motion:

T−mg=mv2l

⇒T=mg+m(2gh)l⇒T=mg(1+2hl)

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