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Q.

A simple pendulum of length one meter has a bob of mass 100g. It is displaced through an angle 60⁰ from the vertical and then released. Kinetic energy of the bob when it passes through the mean position (g = 10 m/s²)

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a

10J

b

0.5J

c

0.05J

d

5J

answer is D.

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Detailed Solution

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Gain in K.E. = (1/2 mV² - 0)

Loss in P.E. = mg ( l - l cosθ)

$∴ K . E = \frac{1}{2} m V^{2} = m g l (1 - \cos θ) \Rightarrow K . E = 0.1 \times 10 \times 1 \times (1 - \frac{1}{2}) = 0.5 J$

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