A simple pendulum with a bob of mass m is suspended from the roof of a car moving with horizontal acceleration a

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The string makes an angle of $\tan^{- 1} (a / g)$ with the vertical

The string makes an angle of $s i n^{- 1} (\frac{a}{g})$ with the vertical

The tension in the string is $m \sqrt{a^{2} + g^{2}}$

The tension in the string is $m \sqrt{g^{2} - a^{2}}$

answer is A, C.

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Detailed Solution

$\tan θ = \frac{m a}{m g} = \frac{a}{g}$

$θ = \tan^{- 1} (\frac{a}{g}) T = F_{net} = m \sqrt{a^{2} + g^{2}}$

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