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Q.

A simple seconds pendulum is constructed out of a very thin isotropic string of coefficient of linear exapansion α=20X10-4 C -1  0  and a heavy particle attached to one end . The free end of the string suspended from the ceiling of an elevator at rest. The pendulum keeps correct time at 200C. When the temperature rises to 500C, The elevator operator of 60kg being a student of physics accelerates elevator vertically up to keep correct time. The apparent weight of the operator is 

(106y) N Then y=……….

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answer is 6.

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Detailed Solution

T=2πlg

lαgl1l=g1g

l(1+αΔT)l=g+ag

1+αΔT=1+aga=gαΔT

Apparent weight W1=m(g+a)

=m(g+gαΔT)

=mg(1+αΔT)

=60×10×1+20×104×30

106y=636N

y=6

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