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Q.

A simple telescope, consisting of an objective of focal length 60cm and a single eye lens of focal length 5cm is focused on a distance object in such a way that parallel rays emerge from the eye lens. If the object makes an angle of $2^{0}$ at the objective, the angular width of the image is

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a

$48^{0}$

b

$10^{0}$

c

$50^{0}$

d

$24^{0}$

answer is B.

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Detailed Solution

$\begin{array}{l} m = \frac{f_{0}}{f_{e}} = \frac{60}{5} = 12 = \frac{θ_{i}}{θ_{0}} \\ θ_{i} = 12 \times 2 = 24^{0} \end{array}$

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A simple telescope, consisting of an objective of focal length 60cm and a single eye lens of focal length 5cm is focused on a distance object in such a way that parallel rays emerge from the eye lens. If the object makes an angle of 20 at the objective, the angular width of the image is