AI Mentor

Check Your IQ

Free Expert Demo

Try Test

Courses

Dropper NEET Course Dropper JEE Course Class - 12 NEET Course Class - 12 JEE Course Class - 11 NEET Course Class - 11 JEE Course Class - 10 Foundation NEET Course Class - 10 Foundation JEE Course Class - 10 CBSE Course Class - 9 Foundation NEET Course Class - 9 Foundation JEE Course Class -9 CBSE Course Class - 8 CBSE Course Class - 7 CBSE Course Class - 6 CBSE Course

Offline Centres

A single conservative force F(x) acts on a 1.0-kg particle that moves along the x-axis. The potential energy U(x) is given by U(x)=20+(x-2)² where x is in metres. At x=5.0m, the particle has a kinetic energy of 20J select the correct options.

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.

An Intiative by Sri Chaitanya

The maximum and minimum values of x, respectively are 7.38 m, -3.38m.

The maximum kinetic energy of the particle and the value of x at which maximum kinetic energy occurs are 29J, 0m.

equation of force F(x) as a function of x is F=2(2-x)

The mechanical energy of the system is 45J

answer is B, D.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

Detailed Solution

(a) At x=5m, U=20+ (s-2)²=29J, K=20J mechanical energy= E= U+K=49J

(b) U_max= $= 49 J \Rightarrow 20 + (X - 2)^{2} = 49 \Rightarrow (X - 2)^{2} = 29$

$\Rightarrow X - 2 = \pm \sqrt{29} \Rightarrow X = - 3.38 M, 7.38 m$

(c) The maximum value of kinetic energy occurs when the potential energy is minimum, U_min=20J so K_max=29J, this occurs at x=2m

d) $F (x) = \frac{- d U}{d x} = - 2 (x - 2) = 2 (2 - x)$

Watch 3-min video & get full concept clarity

courses

No courses found

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Online Course for IIT JEE

Best Online Course for NEET

Best Online Course for CBSE

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Get Expert Academic Guidance – Connect with a Counselor Today!