Q.

A single slit of width a is illuminated by violet light of wavelength 400 nm and the width of the primary  diffraction maximum is measured as y. When half of the slit width is covered and illuminated by red light of wavelength 700 nm, the width of the primary diffraction maximum ny4. Find the value of n

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answer is 14.

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Detailed Solution

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Width of central maximum  =2λDa=y
New width,  y'=2λ'Da'
 y'y=λ'D'a'×aλD=700×D×aa2×400D=144              n=14 
 

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