A singly ionized magnesium atom A = 24 ion is accelerated to kinetic energy 5 keV, and is projected perpendicularly into a magnetic field B of the magnitude 0.5 T. The radius of path formed will be________cm.

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answer is 9.8.

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Detailed Solution

$\begin{array}{rcl} r & = & \frac{p}{qB} = \frac{\sqrt{2 mE}}{qB} = \frac{\sqrt{2 \times 24 \times 1.6 \times 10^{- 27} \times 5 \times 10^{3} \times 1.6 \times 10^{- 19}}}{1.6 \times 10^{- 19} \times 0.5} = \end{array}$ 0.098 m

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