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A siphon in use is demonstrated in the following figure. The density of the liquid flowing in siphon is 1.5 gm/ cc. The pressure difference between the point P and S will be

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$2 \times 10^{5} N / m$

Infinity

$10^{5} N / m$

Zero

answer is C.

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Detailed Solution

As the both points are at the surface of liquid and these points are in the open atmosphere. So both point possess similar pressure and equal to 1 atm. Hence the pressure difference will be zero.

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