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A slab of ice 8 inches in length, 11 inches in breadth, and 2 inches thick was melted and solidified in the form of a rod of 8 inches diameter. The length of such a rod in inches will be

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3 inches

3.5 inches

4 inches

4.5 inches

answer is B.

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Detailed Solution

Dimensions of cubical slab,
Length l= 11 in
Breadth b= 11 in
Thickness t= 11 in
Diameter of rod r= 8 in
Let height of rod = h in
Volume remain same after the recasting.
Volume of cuboid = Volume of rod (cylinder)

l \times b \times t = π \times r^{2} \times h

8 \times 11 \times 2 = \frac{22}{7} \times 4^{2} \times h

h = 8 \times 7 \times \frac{2}{32}

h = \frac{7}{2}

h = 3.5

inches

3.5 inches

Hence, option 2 is correct.

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