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A slab of transparent materials is made as shown in the figure. Monochromatic parallel beams of light are normally incident on the slabs. The thickness of C is twice the thickness of B. The number of waves in A = the number of waves in the combination of B and C. The refractive index of material A $μ_{0} = 1.5$ and that of C $μ_{2} = 1.4$

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The refractive index B is 1.7

The frequency of light in B is two times the frequency of light in C.

The refractive index of B is 1.6

The frequency of light in B is the same as the frequency of light in C.

answer is C, D.

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Detailed Solution

Let thickness of B is x, Then $1.5 (3 x) = μ_{1} (x) + 1.4 (2 x) = μ_{1} = 1.7$

Frequency or Independent of medium, so the frequency of light in B is the same as the frequency of light in C.

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