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Q.

A slit of size 0.15 cm is placed at 2.1 m from a screen. On illuminated it by a light of wavelength 5 × 10–5 cm. The width of central maxima will be  

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a

 0.14 mm

b

 1.4 mm

c

70 mm 

d

 0.14 cm

answer is C.

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Detailed Solution

 Width of central maxima =2λDd =2×2.1×5×10−70.15×10−2=1.4×10−3m=1.4mm

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