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A slit (wavelength $λ = 600$ nm) of adjustable width is used to illuminate two points 0.1 mm apart. Initially, the slit is closed and then gradually it is opened. The width at which the fringes on a screen 2 m apart will just disappear is

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1 mm

2 mm

10 mm

12 mm

answer is D.

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Detailed Solution

$T h e r e q u i r e d a n g u l a r w i d t h i s ϕ = \frac{λ}{d} o r \frac{b}{D} = \frac{λ}{d} ∴ d = \frac{600 \times 10^{- 9}}{0.1 \times 10^{- 3}} \times 2 = 12 \times 10^{- 3} m = 12 m m$

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