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Q.

A small aperture is illuminated with a parallel beam of light of wavelength λ= 628 nm.  The emergent beam has an angular divergence of 20. The size of the aperture is

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a

9 μm

b

18 μm

c

27 μm

d

36 μm

answer is D.

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Detailed Solution

 

as θ is small    aθ=λ\text{as } \theta \text{ is small} \;\Rightarrow\; a\theta = \lambda a=λθ=628×1093.14×180=36μma = \frac{\lambda}{\theta} = \frac{628 \times 10^{-9}}{3.14} \times 180 = 36 \,\mu m

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