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A small aperture is illuminated with a parallel beam of $λ$ = 628 nm. The emergent beam has an angular divergence of 20. The size of the aperture is

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36 µm

27 µm

9 µm

18 µm

answer is B.

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Detailed Solution

$2 θ = 2^{0} \Rightarrow θ = 1^{0} = \frac{π}{180} rad; a \sin θ = λ$ as $θ$ is small $\Rightarrow aθ = λ$
$a = \frac{λ}{θ} = \frac{628 \times 10^{- 9}}{3 .14} \times 180 = 36 μm$

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