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Q.

A small bar magnet has a magnetic moment $1.2 {Am}^{2}$ . The magnetic field at a distance 0.1m on its axis will be $(μ_{0} = 4 π x 10^{- 7} T - m / A)$

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a

$1.2 x 10^{- 4} T$

b

$2.4 x 10^{- 4} T$

c

$2.4 x 10^{4} T$

d

$1.2 x 10^{4} T$

answer is B.

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Detailed Solution

$B = \frac{μ_{0}}{4 π} . \frac{2 M}{d^{3}} \Rightarrow B = 10^{- 7} x \frac{2 x 1.2}{{(0.1)}^{3}} = 2.4 x 10^{- 4} T$

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A small bar magnet has a magnetic moment 1.2 Am2. The magnetic field at a distance 0.1m on its axis will be μ0=4π x 10-7 T-m/A