Q.

A small block is connected to one end of a massless spring of un-stretched length 4.9 m. The other end of the spring (see the figure) is fixed.  The system lies on a horizontal frictionless surface. The block is stretched by 0.2m and released from rest at t=0.  It then executes simple harmonic motion with angular frequency ω=π3  rad/s. Simultaneously at t=0, a small pebble is projected with speed v from point P at  an angle of  450 as shown in the figure. Point P is at a horizontal distance of 10m  from O.  If the pebble hits the block at t=1sec, the initial speed of pebble is v=x  m/s.  The value of x is (take g= 10 m/s2)

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answer is 50.

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Detailed Solution

For the block T=2πω=6seconds

 For block, the position in 1 seconds

Will be x=0.2  coswt

x=0.2cos2π6×1

x=0.2×12

x=0.1m

 At t=1sec block will be at a distance 4.9m+0.1m=5m from wall

  Range of pebble is also 5m Now, for pebble,

Vcos450×1s=5m

 V=50  m/s

  x=50

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A small block is connected to one end of a massless spring of un-stretched length 4.9 m. The other end of the spring (see the figure) is fixed.  The system lies on a horizontal frictionless surface. The block is stretched by 0.2m and released from rest at t=0.  It then executes simple harmonic motion with angular frequency ω=π3  rad/s. Simultaneously at t=0, a small pebble is projected with speed v from point P at  an angle of  450 as shown in the figure. Point P is at a horizontal distance of 10 m  from O.  If the pebble hits the block at t=1sec, the initial speed of pebble is v=x  m/s.  The value of x is (take g= 10 m/s2)