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A small block of mass 100 g moves with uniform speed in a horizontal circular groove, with vertical side walls, of radius 25 cm. If the block takes 2.0s to complete one round, the normal contact force by the side wall of the groove is______ $\times 10^{- 3}$ (take $π^{2} = 10$ )

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Detailed Solution

The speed of the block is $v = \frac{2 π (25 \times 10^{- 2})}{2} = 0.785 \frac{m}{s}$ The only force in this direction is the normal contact force due to the side walls. Thus from Newton’s second low, this force is $N = \frac{m v^{2}}{r}$

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