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Q.

A small block slides down on a smooth inclined plane, starting from rest at time t=0 .Let Sn be the distance travelled by the block in the interval t=n-1 to t=n. Then, the ratio SnSn+1 is :

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a

2n+12n-1

b

2n2n1

c

2n12n

d

2n12n+1

answer is C.

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Detailed Solution

Sn=0+12a(2n1)Sn+1=0+12a(2(n+1)1)=12a(2n+1)SnSn+1=(2n1)(2n+1)

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