A small candle 2.5 cm in size is placed at 27 cm in front of a concave mirror of radius of curvature 36 cm. Then

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The distance from the mirror should be a screen be placed in order to obtain a sharp image is 54 cm

The distance from the mirror should be a screen be placed in order to obtain a sharp image is 27 cm

Size of the image is 5 cm real,inverted and magnified in nature

Size of the image is 10 cm real,inverted and magnified in nature

answer is A, C.

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Detailed Solution

R=-36 cm
$f = \frac{R}{2} = - 18 c m, u = - 27 c m$
Height of object $O = 2.5 c m$
Use the mirror formula $\frac{1}{f} = \frac{1}{v} + \frac{1}{u}$
We get v = -54 cm
Let the size of image be I

$\begin{array}{l} m = - \frac{v}{u} = \frac{I}{O} \\ I = - 5 c m \end{array}$

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