A small candle 2.5 cm in size is placed at 27 cm in front of a concave mirror of radius of curvature 36 cm. A screen is placed in order to obtain a sharp image? What are the nature and size of image?

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real, inverted, magnified, 5cm

real, inverted, diminished, 4 cm

erected, magnified, 5cm

erected, magnified, 54 cm

answer is B.

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Detailed Solution

$\frac{1}{f} = \frac{1}{v} + \frac{1}{u} \Rightarrow \frac{1}{- 18} = \frac{1}{v} + \frac{1}{- 27} \Rightarrow v = - 54 cm$

$m = \frac{- v}{u} = \frac{h_{i}}{h_{0}}$

$∴ h^{'} = - 5 cm$

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