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A small capillary tube of length 100 cm closed at one end is kept horizontally and a mercury column of length 10 cm is exactly in the middle. If the atmospheric pressure is 1 atm then identify the correct option(s).

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The pressure of "air trapped" in the original horizontal position is 750 mm of Hg.

The length of the air trapped when the tube is held vertically with open end upwards is,

$\frac{45 \times 76}{86} cm$

The length of the air trapped when the tube· held vertically with open end downwards is

$\frac{45 \times 76}{66} cm$

No air will be trapped when it is held vertically with open end downward

answer is B, C.

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Detailed Solution

(b) $P_{1} l_{1} = P_{2} l_{2}$

$76 \times 45 = 86 \times I_{2}$

$76 \times 45 = 66 \times l_{2}$

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