A small indoor greenhouse (herbarium) is made entirely of glass panes (including base) held together with tape. It is 30 cm long, 25 cm wide and 25 cm high.

(i) What is the area of the glass?

(ii) How much of tape is needed for all the 12 edges?

Given:

Length (l) = 30cm

Breadth (b) = 25 cm

Height (h) = 25 cm

(i)Total surface area of the cuboid = 2(lb + bh + hl)

The area of the glass = 2(lb + bh + hl)

= 2 × (30 cm × 25 cm + 25 cm × 25 cm + 25 cm × 30 cm)

= 2 × (750 cm² + 625 cm² + 750 cm²)

= 2 × 2125 cm²

= 4250 cm²

The total surface area of the glass is 4250 cm²

(ii)

From the figure, tape is required along sides AB, BC, CD, DA, EF, FG, GH, HE, AH, BE, DG, and CF.

Total length of tape = 4(l+b+h)

= [4(30+25+25)] (after substituting the values)

= 320 cm

Therefore, 320 cm tape is required for all 12 edges.