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Q.

A small object at rest, absorbs a light pulse of power 20mW and duration 300ns. Assuming speed of light as 3×108 m/s , the momentum of the object becomes equal to:

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a

0.5×10−17 kg m/s

b

1×10−17 kg m/s

c

2×10−17 kg m/s

d

3×10−17 kg m/s

answer is B.

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Detailed Solution

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P=momentum of photons   =PtC=2×10−17kg m/s
 ∴ momentum of object  =P=2×10−17kg m/s

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