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Q.

A small piece of metal wire is dragged across the gap between the pole pieces of a magnet in 0.5 s. The magnetic flux between the pole pieces is 8×10-4wb then the e.m.f induced in the wire is

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a

1.0×10−3 v

b

1.6×10−3 v

c

1.8×10−3 v

d

2×10−3 v

answer is B.

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Detailed Solution

e. m. f induced in the wire ε=−dϕdt

ε=8×10−40.5=1.6×10−3 volt

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