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A small piece of wire bent into an L shape, with upright and horizontal portions of equal lengths, is placed with the horizontal portion along the axis of the concave mirror whose radius of curvature is 10 cm. If the bend is 20 cm from the pole of the mirror, then the ratio of the lengths of the images of the upright and horizontal portions of the wire is

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1 : 2

3 : 1

3 : 2

2 : 1

answer is B.

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Detailed Solution

Given, u=−20 ; f=−5. From mirror formula we will get $v = - \frac{20}{3} c m$ .

Magnification = $- \frac{v}{u} = - \frac{1}{3}$ and lateral magnification $\frac{f^{2}}{{(u - f)}^{2}}$ = $\frac{1}{9}$ . So the required ratio will become 3 : 1

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