A small sphere of mass m=1 kg is moving with a velocity (4i^−j^) m/s. It hits a fixed smooth wall and rebounds with velocity (i^+3j^) m/s. The coefficient of restitution between the sphere and the wall is n/16 the value of n

∫N dt=1[(i^+3j^)−(4i^−j^)]=− 3i^+4j^Component of 4i^−j^ along − 3i^+4j^=−12−425(− 3i^+4j^)=−1625(− 3i^+4j^)Speed of approach =162525=165Component of i^+3j^ along − 3i^+4j^ is − 3+1225(− 3i^+4j^)Speed of separation =9/5Speed of separation =e×speed of approache=916 or n=9

AI Mentor

Check Your IQ

Free Expert Demo

Try Test

Courses

Dropper NEET Course Dropper JEE Course Class - 12 NEET Course Class - 12 JEE Course Class - 11 NEET Course Class - 11 JEE Course Class - 10 Foundation NEET Course Class - 10 Foundation JEE Course Class - 10 CBSE Course Class - 9 Foundation NEET Course Class - 9 Foundation JEE Course Class -9 CBSE Course Class - 8 CBSE Course Class - 7 CBSE Course Class - 6 CBSE Course

Offline Centres

A small sphere of mass $m = 1 k g$ is moving with a velocity $(4 \hat{i} - \hat{j}) m / s .$ It hits a fixed smooth wall and rebounds with velocity $(\hat{i} + 3 \hat{j}) m / s .$ The coefficient of restitution between the sphere and the wall is $n / 16$ the value of $n$

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.

An Intiative by Sri Chaitanya

answer is 9.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

Detailed Solution

$\int N d t = 1 [(\hat{i} + 3 \hat{j}) - (4 \hat{i} - \hat{j})] = - 3 \hat{i} + 4 \hat{j}$

Component of $4 \hat{i} - \hat{j}$ along $- 3 \hat{i} + 4 \hat{j} = \frac{- 12 - 4}{25} (- 3 \hat{i} + 4 \hat{j}) = - \frac{16}{25} (- 3 \hat{i} + 4 \hat{j})$