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Q.

A small steel sphere of mass m is tied to a string of length r and is whirled in a horizontal circle with a uniform angular velocity 3ω. The string is suddenly pulled, so that radius of the circle is halved. The new angular velocity will be

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a

3ω

b

8ω

c

12ω

d

6ω

answer is D.

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Detailed Solution

As the angular momentum is conserved 

Therefore I1ω1=I2ω2 or mr23ω=mr22ω2 

ω2=12ω .

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