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A smooth light rod not reaching the rough floor is inserted between two identical blocks. A horizontal force F is applied to upper end of rod. The contact force between block A and rod is $F_{1}$ and contact force between block B and rod is $F_{2}$ . Then,

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$F_{1} = F_{2}$

$F_{1} > F_{2}$

$F_{1} < F_{2}$

$F_{1} = 0 a n d F_{2} > 0$

answer is C.

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Detailed Solution

From free body diagram of light rod

$F + F_{1} = F_{2} F_{1} < F_{2}$

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