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Q.

A smooth ring P of mass m can slide on a fixed horizontal rod. A string tied to the ring passes over a fixed pulley and carries a block Q of mass (m/2) as shown in the figure. At an instant the system is released when, the string between the ring and the pulley makes an angle 60° with the rod. The acceleration of the ring at that instant is

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a

2g5

b

2g3

c

g3

d

2g9

answer is C.

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Detailed Solution

mg2−T=ma12                      ...(i)

Tcos60°=ma2                   ...(ii)

a2cos60°=a1                       ...(iii)

Solving (i) and (iii),
Acceleration of ring =2g9

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