A smuggler, smuggles gold in the form of following statue.
When police caught him, 19.7 kg of gold was recovered from the smuggler. How many atoms of gold were recovered (Au = 197) ?

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100

$6 .02 \times 10^{23}$

$6 .02 \times 10^{24}$

$6 .02 \times 10^{25}$

answer is D.

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Detailed Solution

$197 g of Au \to 6.023 \times 10^{23} atoms$
$19.7 \times 10^{3} g of$ →x atoms of Au
$Then, x = \frac{6 .023 \times 10^{23} atoms}{197 g of Au} \times 19 .7 kg \times \frac{10^{3} g}{1 kg}$
$∴ x = 6 .023 \times 10^{25}$

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