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A soap bubble has radius r. The work done in increasing its radius to three times its original radius, without any rise of temperature, is (Given: surface tension of soap solution is T)

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$12 {πr}^{2} T$

$16 {πr}^{2} T$

$64 {πr}^{2} T$

$48 {πr}^{2} T$

answer is C.

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Detailed Solution

$W = [2 \times 4 π {(3 r)}^{2} - 2 \times 4 {πr}^{2}] T = 64 {πr}^{2} T$

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