A soap film is formed in a circular frame loop of thread is lying on the film. If the film inside the loop is broken then the tension in the thread will be

The circular frame is used to form the film.
And we know that fluid tends to reduce surface area.
Therefore, in order to reduce the surface area, the fluid will have tension applied to its surface.
If there is tension at any point on the ring's surface, it is denoted by the letter T.
We now have a thread that is 2πr long. Therefore, in order to produce a ring with a thread of a certain length, we must apply the same amount of tension to each thread point.
Thus, the thread's overall surface tension at the specified length will be

$$\begin{gathered} \mathrm{Length} \mathrm{of} \mathrm{thread}\times \mathrm{tension} \mathrm{on} \mathrm{single} \mathrm{point} \mathrm{of} \mathrm{thread} \\ =2\mathrm{\pi rT} \end{gathered}$$

Hence the correct answer is $2\mathrm{\pi rT}.$