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Q.

A soap film is made by dropping a circular frame of radius b in soap solution.  A bubble is formed by blowing air with speed v in the form of a cylinder.  Air stops after striking surface of soap bubble.  Density of air is ρ.  The radius of the bubble is R>b.  The radius R of the bubble when the soap bubble separates from the ring is βTρv2Find the value of β.  (where, T is the surface tension of the liquid)

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answer is 4.

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Detailed Solution

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Mass of air entering in 1s is m=πb2vρ

 Change in momentum in 1s=mv0=πb2ρv2

Thus, F=πb2ρv2

Pressure due to this force is Δp=FA=πb2ρv2πb2=ρv2

When this excess pressure equals to 4TR,the bubble gets separated

ρv2=4TRR=4Tρv2
So, β=4.

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