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A sodium salt on treatment with MgCl₂ gives white precipitate only on heating. The anion of the sodium salt is:

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${HCO}_{3}^{-}$

${CO}_{3}^{2 -}$

${NO}_{3}^{-}$

${SO}_{4}^{2 -}$

answer is A.

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Detailed Solution

${HCO}_{3}^{-}$ will be the anion of the sodium bicarbonate salt.

Magnesium bicarbonate, which is likewise soluble in water, is obtained when sodium bicarbonate combines with .

However, when ${MgCl}_{2}$ is heated ${HCO}_{3}^{-}$ is produced, which results in a white precipitate.

Hence, the correct option is A.

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