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Q.

A sodium salt on treatment with ${MgCl}_{2}$ gives white precipitate only on heating. The anion of the sodium salt is

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a

${NO}_{3}$

b

${SO}_{4}^{2 -}$

c

${CO}_{3}^{2 -}$

d

${HCO}_{3}^{-}$

answer is A.

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Detailed Solution

${MgCl}_{2} + 2 {NaHCO}_{3} \to Mg {({HCO}_{3})}_{2} (a q) + 2 NaCl$

$Mg {({HCO}_{3})}_{2} (a q) \overset{∆}{\to} {MgCO}_{3} ↓ + H_{2} O + {CO}_{2} ↑ (white ppt)$

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