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A solenoid has a core of material with relative permeability 400. The windings of solenoid are insulated from the core and carry a current of 2 A. If no. of turns per unit length is 1000, the magnetising current

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2 A

8 A

798 A

700 A

answer is C.

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Detailed Solution

If i is current in solenoid and i_m is magnetization current

$B = μni = μ_{0} n (i + i_{m}); μ_{0} μ_{r} ni = μ_{0} n (i + i_{m}) i_{m} = (μ_{r} - 1) i = (400 - 1) x 2 = 399 x 2 = 798 A$

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