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Q.

A solenoid is of length 50 cm and has a radius of 2cm.  It has 500 turns.  Around its central section a coil of 50 turns is wound. Calculate the mutual inductance of the system. (in μH ) (Round off to the Nearest Integer)

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answer is 79.

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Detailed Solution

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NP=500,NS=50;A=π×0.02×0.02m2

μ0=4π×107Hm1,1=50cm=0.5m

Now, M=μ0NPNSAl=4π×107×500×50×π×(0.02)20.5H

=789.8×107H=78.98μH

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