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A solenoid of 1000 turns per metre has a core with relative permeability 500. Insulated winding of the solenoid carry an electric current of 5 A. The magnetic flux density produced by the solenoid is: (permeability of free space $= 4 π \times 10^{- 7} H/m$ )

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$2 \times 10^{- 3} π T$

$10^{- 4} π T$

$\frac{π}{5} T$

$π T$

answer is D.

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Detailed Solution

Magnetic flux density $= B = μni = μ_{0} μ_{r} ni$ $= 500 (4 π \times 10^{- 7}) (1000) 5$ $= 10000000 π \times 10^{- 7}$ $= π T$

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