A solenoid of 1200 turns is wound uniformly in a single layer on a glass tube 2m long and 0.2 m in diameter. The magnetic intensity at the center of the solenoid when a current of 2A flows through it is :

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${2.4×10}^{- 3} {Am}^{- 1}$

${1.2×10}^{3} {Am}^{- 1}$

1Am^-1

${2.4×10}^{3} {Am}^{- 1}$

answer is B.

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Detailed Solution

We are given the following data:

Formula to calculate magnetic field intensity (H) inside a solenoid:

H = (N / L) × I

Number of turns per unit length = N / L = 1200 / 2 = 600 turns/m

H = 600 turns/m × 2 A = 1200 A/m

Final Answer

The magnetic intensity at the center of the solenoid is 1.2 × 10³ A/m.

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