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Q.

A solid ball of mass 10 kg at 40°C is gently placed in a liquid of mass 20 kg at 20°C and of specific heat capacity 1 cal/gm-°C. When the thermal equilibrium is attained, temperature of the system is 35°C. The specific heat capacity of solid ball is. Neglect heat capacity of the vessel.

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a

2  cal/gm/0C

b

1 cal/gm/0C

c

3  cal/gm/0C

d

6  cal/gm/0C

answer is D.

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Detailed Solution

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heat gain by liquid = heat loss by solid ball.

⇒ 20 ×1×15 =10×S×5  ⇒S = 6 cal/gm/0C

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