A solid cylinder length is suspended symmetrically through two massless strings, as shown in the figure. The distance from the initial rest position, the cylinder should fall by unwinding the strings to achieve a speed of 4 ms^–1, is…….cm.
(Take g = 10 ms^–2 )

see full answer

Start JEE / NEET / Foundation preparation at rupees 99/day !!

21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!

An Intiative by Sri Chaitanya

answer is 120.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

From energy conservation

$\begin{array}{l} mgh = \frac{1}{2} {mv}^{2} + \frac{1}{2} {Iω}^{2} \\ mgh = \frac{1}{2} {mv}^{2} + \frac{1}{2} \frac{{mR}^{2}}{2} ω^{2} \\ 10 h = \frac{16}{2} + \frac{16}{4} \Rightarrow h = 1 .2 m = 120 cm \end{array}$

Watch 3-min video & get full concept clarity

hear from our champions

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Books for IIT JEE

Best Books for NEET

🔥 Start Your JEE/NEET Prep at Just ₹1999 / month - Limited Offer! Check Now!

Get Expert Academic Guidance – Connect with a Counselor Today!